Wie kann ich das anstellen das eine Grafik angezeigt wird wenn mann zb. eingeloggt ist oder ausgeblendet wird wenn man ausgeloggt ist ?
Ich denke hier ist was falsch weil es nicht geht:
<?php
?>
<?//usermenü wenn eingeloogt
//print "-> ".$HTTP_COOKIE_VARS["$LOGGED_IN_NICK"];
//print urlencode($sessionID);
if(!empty($HTTP_COOKIE_VARS["$LOGGED_IN_NICK"])) // sollte aber eigentlich immer der Fall sein
{
$bm_user_nick = $HTTP_COOKIE_VARS["$LOGGED_IN_NICK"];
if (!empty($pwsafe))
{
$bm_password = $HTTP_COOKIE_VARS["$LOGGED_IN_PW"];
}
$bm_query = "select id from users where nick='$bm_user_nick'";
$bm_result = mysql_query($bm_query);
$user_id = mysql_result($bm_result,0,"id");
//print $user_id;
if($bm_result)
{
?>
<table align = "center" style ="width:90%;height25px;border:0px;" cellpadding="0" cellspacing="0">
<form action = "redirect.php" method = "post">
<tr><td height = "20" align="right">Hallo <?=$bm_user_nick;?></td>
</tr>
<input type="hidden" name="SESSION_ID" value="<?=urlencode($sessionID);?>">
<input type="hidden" name="user_id" value="<?=$user_id;?>">
<tr><td width="900" align="center" valign="top" height ="23">
<div align="left">
<input type = "image" src ="./images/header/usermenue.jpg" name="btnusermenue">
</div></td></tr>
</form>
</table>
<?}}else{?>
<table align = "center" style ="table-layout:fixed;width:90%;height25px;border:0px;" cellpadding="0" cellspacing="0">
<form action = "redirect.php" method = "post">
<tr><td height = "20" align="right">Hallo Gast!</td>
</tr>
<input type="hidden" name="SESSION_ID" value="<?=urlencode($sessionID);?>">
<input type="hidden" name="user_id" value="<?=$user_id;?>">
<tr><td align="center" valign="top" height ="23">
<div align="left">
<input type = "image" src ="./images/header/gastmenue.jpg" name="btngastmenue">
</div></td></tr>
</form>
</table>
<?}?>
ich hoffe das mir einer Helfen kann....
) danke schonmal
Ich denke hier ist was falsch weil es nicht geht:
<?php
?>
<?//usermenü wenn eingeloogt
//print "-> ".$HTTP_COOKIE_VARS["$LOGGED_IN_NICK"];
//print urlencode($sessionID);
if(!empty($HTTP_COOKIE_VARS["$LOGGED_IN_NICK"])) // sollte aber eigentlich immer der Fall sein
{
$bm_user_nick = $HTTP_COOKIE_VARS["$LOGGED_IN_NICK"];
if (!empty($pwsafe))
{
$bm_password = $HTTP_COOKIE_VARS["$LOGGED_IN_PW"];
}
$bm_query = "select id from users where nick='$bm_user_nick'";
$bm_result = mysql_query($bm_query);
$user_id = mysql_result($bm_result,0,"id");
//print $user_id;
if($bm_result)
{
?>
<table align = "center" style ="width:90%;height25px;border:0px;" cellpadding="0" cellspacing="0">
<form action = "redirect.php" method = "post">
<tr><td height = "20" align="right">Hallo <?=$bm_user_nick;?></td>
</tr>
<input type="hidden" name="SESSION_ID" value="<?=urlencode($sessionID);?>">
<input type="hidden" name="user_id" value="<?=$user_id;?>">
<tr><td width="900" align="center" valign="top" height ="23">
<div align="left">
<input type = "image" src ="./images/header/usermenue.jpg" name="btnusermenue">
</div></td></tr>
</form>
</table>
<?}}else{?>
<table align = "center" style ="table-layout:fixed;width:90%;height25px;border:0px;" cellpadding="0" cellspacing="0">
<form action = "redirect.php" method = "post">
<tr><td height = "20" align="right">Hallo Gast!</td>
</tr>
<input type="hidden" name="SESSION_ID" value="<?=urlencode($sessionID);?>">
<input type="hidden" name="user_id" value="<?=$user_id;?>">
<tr><td align="center" valign="top" height ="23">
<div align="left">
<input type = "image" src ="./images/header/gastmenue.jpg" name="btngastmenue">
</div></td></tr>
</form>
</table>
<?}?>
ich hoffe das mir einer Helfen kann....